From bef099fee6f5a24036d1f02fcc43fe4b849c5528 Mon Sep 17 00:00:00 2001
From: Dave Gauer <dave@ratfactor.com>
Date: Sun, 30 Apr 2023 17:11:37 -0400
Subject: Renamed 095 to "for3" to match feature sequence

So 100 will be the next in line.
---
 exercises/095_for3.zig | 73 ++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 73 insertions(+)
 create mode 100644 exercises/095_for3.zig

(limited to 'exercises/095_for3.zig')

diff --git a/exercises/095_for3.zig b/exercises/095_for3.zig
new file mode 100644
index 0000000..e4c4662
--- /dev/null
+++ b/exercises/095_for3.zig
@@ -0,0 +1,73 @@
+//
+// The Zig language is in rapid development and continuously
+// improves the language constructs. Ziglings evolves with it.
+//
+// Until version 0.11, Zig's 'for' loops did not directly
+// replicate the functionality of the C-style: "for(a;b;c)"
+// which are so well suited for iterating over a numeric
+// sequence.
+//
+// Instead, 'while' loops with counters clumsily stood in their
+// place:
+//
+//     var i: usize = 0;
+//     while (i < 10) : (i += 1) {
+//         // Here variable 'i' will have each value 0 to 9.
+//     }
+//
+// But here we are in the glorious future and Zig's 'for' loops
+// can now take this form:
+//
+//     for (0..10) |i| {
+//         // Here variable 'i' will have each value 0 to 9.
+//     }
+//
+// The key to understanding this example is to know that '0..9'
+// uses the new range syntax:
+//
+//     0..10 is a range from 0 to 9
+//     1..4  is a range from 1 to 3
+//
+// At the moment, ranges are only supported in 'for' loops.
+//
+// Perhaps you recall Exercise 13? We were printing a numeric
+// sequence like so:
+//
+//     var n: u32 = 1;
+//
+//     // I want to print every number between 1 and 20 that is NOT
+//     // divisible by 3 or 5.
+//     while (n <= 20) : (n += 1) {
+//         // The '%' symbol is the "modulo" operator and it
+//         // returns the remainder after division.
+//         if (n % 3 == 0) continue;
+//         if (n % 5 == 0) continue;
+//         std.debug.print("{} ", .{n});
+//     }
+//
+//  Let's try out the new form of 'for' to re-implement that
+//  exercise:
+//
+const std = @import("std");
+
+pub fn main() void {
+
+    // I want to print every number between 1 and 20 that is NOT
+    // divisible by 3 or 5.
+    for (???) |n| {
+
+        // The '%' symbol is the "modulo" operator and it
+        // returns the remainder after division.
+        if (n % 3 == 0) continue;
+        if (n % 5 == 0) continue;
+        std.debug.print("{} ", .{n});
+    }
+
+    std.debug.print("\n", .{});
+}
+//
+// That's a bit nicer, right?
+//
+// Of course, both 'while' and 'for' have different advantages.
+// Exercises 11, 12, and 14 would NOT be simplified by switching
+// a 'while' for a 'for'.
-- 
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